56 lines
1.6 KiB
Python
56 lines
1.6 KiB
Python
from functools import lru_cache
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import math
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def str2int(dt: str):
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a = []
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maxInt = 0
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# 遍历输入的字符串
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for i in dt:
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# 使用ord函数将每个字符转换为对应的ASCII码，生成整数流
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this = ord(i)
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if this >maxInt:
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maxInt = this
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a.append(str(this))
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IntSize = len(str(maxInt))
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out = str(IntSize)
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for i in a:
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i.zfill(IntSize)
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# 将处理后的整数字符串添加到输出字符串中
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out += i
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return int(out)
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def int2str(dt: list[int]):
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# 遍历整数列表
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a = []
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for i in dt:
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# 使用chr函数将每个整数转换为对应的字符，生成字节流
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a.append(chr(i))
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return a
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def list2int(dt: list[str]):
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# 防止第一个数为零
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maxInt = max(dt)
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IntSize = len(str(maxInt))
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out = str(IntSize)
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# 遍历整数列表
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for i in dt:
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# 将整数转换为字符串
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i = str(i)
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# 如果字符串长度小于3，则在前面补0，使其长度为3
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if len(i) < IntSize:
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while len(i) < IntSize:
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i = '0' + i
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# 将处理后的整数字符串添加到输出字符串中
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out += i
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# 将结果字符串转换为整数并返回
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return int(out)
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def int2list(dt: int):
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# 将整数转换为字符串，并去掉前面的'100'
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size = int(str(dt)[0])
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dt = str(dt)[1:]
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# 将字符串按照每3个字符分割为子列表
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sub_lists = [dt[i:i+size] for i in range(0, len(dt), size)]
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# 遍历子列表并将其转换为整数后返回
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for i in sub_lists:
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yield int(i) |